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Diffstat (limited to 'results/classifier/qwen3:32b/reasoning/instruction/2483')
| -rw-r--r-- | results/classifier/qwen3:32b/reasoning/instruction/2483 | 19 |
1 files changed, 19 insertions, 0 deletions
diff --git a/results/classifier/qwen3:32b/reasoning/instruction/2483 b/results/classifier/qwen3:32b/reasoning/instruction/2483 new file mode 100644 index 00000000..8ab0150b --- /dev/null +++ b/results/classifier/qwen3:32b/reasoning/instruction/2483 @@ -0,0 +1,19 @@ +<think> +Okay, let's see. The user is reporting an issue with the m68k architecture in QEMU. The problem is with the JSR (Jump to Subroutine) instruction. They provided some assembly code and a description of what's happening. + +So, the code is moving the stack pointer (SP) into A1, then copying 0x68 bytes from A0 to A1. Then there's a loop that does this byte copy, decrementing D0 each time until it's zero. After that, the JSR (SP) is called. + +The user says that SP is 0x3bfc at the JSR. Normally, JSR (SP) would jump to the address in SP (so 0x3bfc) and push the return address onto the stack. But in QEMU, the return address is being placed at 0xb3f8 (which seems like a reversed byte order), and the PC ends up at 0x3bf8, executing the return address as code. That's causing issues. + +Hmm, the problem here seems to be with how the JSR instruction is being emulated. The JSR instruction on the m68k should push the return address (the address of the next instruction) onto the stack and then jump to the target address. But in this case, the stack pointer manipulation might be causing unexpected behavior because the code is using SP directly. + +The user mentions that the stack pointer is being used as the target address for JSR. If the code is modifying the stack pointer (like moving it to A1 and copying data to where SP points), then the JSR might be trying to jump to an address that's on the stack, but the way QEMU is handling the stack pointer during the JSR could be incorrect. + +The key issue here is that JSR is supposed to push the return address onto the stack. If the stack pointer isn't being handled correctly during this instruction, then the return address would be placed in the wrong location, leading to the PC jumping to an incorrect address. The user's example shows that the return address is at 0xb3f8 instead of 0x3bf8, which suggests an endianness issue or incorrect stack pointer adjustment. + +Since the problem is related to the execution of the JSR instruction and how the stack is being manipulated during its execution, this falls under an instruction-related bug. The QEMU emulator's m68k CPU implementation might have a mistake in how it handles the JSR instruction, particularly when the operand is the stack pointer itself. + +Therefore, the category is "instruction". +</think> + +instruction \ No newline at end of file |