qemu-system-x86_64: stuck on watchpoint hit
Description of problem:

Steps to reproduce:
1. `gcc -O0 -g watch-bug.c -o watch-bug`
2. `gdb watch-bug`
3. gdb commands:
```
b main
r
watch l1
next  [ correct stop on the next line ]
next  [ qemu is stuck as watchpoint should be hit ]
```
Additional information:
* NOTE: it works correctly, if 'continue' command is used instead of 'next'


`watch-bug.c`
```c
int i0;
long l1;


int main(int argc, char* argv[])
{
    i0 = argc;
	l1 = i0 * 7;

    return 0;
}

```

Log:
```c
Log:
root@qemux86-64:~# gdb watch-bug
GNU gdb (GDB) 13.2
Copyright (C) 2023 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>
This is free software: you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law.
Type "show copying" and "show warranty" for details.
This GDB was configured as "x86_64-poky-linux".
Type "show configuration" for configuration details.
For bug reporting instructions, please see:
<https://www.gnu.org/software/gdb/bugs/>.
Find the GDB manual and other documentation resources online at:
    <http://www.gnu.org/software/gdb/documentation/>.

For help, type "help".
Type "apropos word" to search for commands related to "word"...
Reading symbols from watch-bug...
(gdb) b main
Breakpoint 1 at 0x1134: file watch-bug.c, line 8.
(gdb) r
Starting program: /home/root/watch-bug 
[Thread debugging using libthread_db enabled]
Using host libthread_db library "/lib/libthread_db.so.1".

Breakpoint 1, main (argc=1, argv=0x7fffffffecd8) at watch-bug.c:8
8           i0 = argc;
(gdb) watch l1
Hardware watchpoint 2: l1
(gdb) next
9           l1 = i0 * 7;
(gdb) next
```