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-assembly: 0.966
-debug: 0.947
-peripherals: 0.845
-graphic: 0.763
-device: 0.739
-performance: 0.675
-architecture: 0.668
-risc-v: 0.662
-PID: 0.627
-ppc: 0.621
-socket: 0.587
-permissions: 0.578
-semantic: 0.570
-vnc: 0.566
-network: 0.501
-kernel: 0.492
-x86: 0.485
-user-level: 0.483
-arm: 0.432
-mistranslation: 0.395
-i386: 0.383
-boot: 0.358
-virtual: 0.302
-register: 0.249
-files: 0.203
-VMM: 0.200
-hypervisor: 0.198
-TCG: 0.161
-KVM: 0.081
-
-riscv virt pflash0 writes not supported
-Description of problem:
-I am using GDB to debug some Firmware related stuff. At some point in the execution my BIOS/Firmware writes into some global variable (at 0x2000525C)  inside the .bss section which is linked to be inside the memory mapped pflash0. But when I step forward with GDB to the exact location where the store instruction (sw) is executed, QEMU prints the following:
-```
-pflash_write: Unimplemented flash cmd sequence (offset 000000000000525c, wcycle 0x0 cmd 0x0 value 0x1)
-```
-According to the top of `hw/block/pflash_cfi01.c` Flash writes are supported. I was also under the impression that the flash is memory mapped, but maybe that is not true? I am probably missing something here so it would be nice if someone could point me in the right direction. I would also gladly contribute if there is something missing in the riscv virt target. 
-
-I made a simple program to more easily reproduce this:
-```
-.section .text
-.global _start
-_start:
-	lui a5, 0x20000
-	li a4, 5
-	sw a4, 24(a5)
-
-```
-results in QEMU error msg:
-```
-pflash_write: Unimplemented flash cmd sequence (offset 0000000000000018, wcycle 0x0 cmd 0x0 value 0x5)
-```
-Steps to reproduce:
-1. compile above assembly program like this:
-```
-riscv64-unknown-elf-gcc -nostdlib -O0 bios.S
-riscv64-unknown-elf-objcopy -O binary a.out
-truncate -s 33554432 a.out
-```
-2. start QEMU like this:
-```
-qemu-system-riscv64 -M virt -bios none -drive if=pflash,format=raw,unit=0,file=a.out -nographic -d unimp
-```
-3. notice the error message printed by QEMU