virtio-serial: Handle scatter/gather input from the guest

Current guests don't send more than one iov but it can change later.
Ensure we handle that case.

Signed-off-by: Amit Shah <amit.shah@redhat.com>
CC: Avi Kivity <avi@redhat.com>
Signed-off-by: Anthony Liguori <aliguori@us.ibm.com>

1 files changed, 8 insertions, 4 deletions

diff --git a/hw/virtio-serial-bus.c b/hw/virtio-serial-bus.c
index b8410c3bb8..3053a35c39 100644
--- a/hw/virtio-serial-bus.c
+++ b/hw/virtio-serial-bus.c
@@ -351,7 +351,8 @@ static void handle_output(VirtIODevice *vdev, VirtQueue *vq)
 
     while (virtqueue_pop(vq, &elem)) {
         VirtIOSerialPort *port;
-        size_t ret;
+        uint8_t *buf;
+        size_t ret, buf_size;
 
         port = find_port_by_vq(vser, vq);
         if (!port) {
@@ -374,9 +375,12 @@ static void handle_output(VirtIODevice *vdev, VirtQueue *vq)
             goto next_buf;
         }
 
-        /* The guest always sends only one sg */
-        ret = port->info->have_data(port, elem.out_sg[0].iov_base,
-                                    elem.out_sg[0].iov_len);
+        buf_size = iov_size(elem.out_sg, elem.out_num);
+        buf = qemu_malloc(buf_size);
+        ret = iov_to_buf(elem.out_sg, elem.out_num, buf, 0, buf_size);
+
+        ret = port->info->have_data(port, buf, ret);
+        qemu_free(buf);
 
     next_buf:
         virtqueue_push(vq, &elem, ret);