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instruction: 0.466
runtime: 0.409
syscall: 0.125



ARM conditional branch after if-then instruction not working

Hello

There seems to be an issue with QEMU when debugging if-then condition blocks from the thumb2 instruction set. The following snippet runs fine during normal execution, but keeps hanging at the conditional branch when debugging. The jump at the branch should only be executed as long as $r0 is lower than $r1. Problem is that once both are equal, the execution is not continued past the branch and the program counter never gets popped.

2000407a:   push    {lr}
2000407c:   movs    r0, r6
2000407e:   ldmia   r7!, {r1, r6}
20004080:   push    {r0, r1}
20004082:   str.w   r6, [r7, #-4]!
20004086:   ldr     r6, [sp, #0]
20004088:   pop     {r0, r1}
2000408a:   adds    r0, #1
2000408c:   cmp     r0, r1
2000408e:   itt     lt
20004090:   pushlt  {r0, r1}
20004092:   blt.w   0x20004082      ; unpredictable <IT:lt>  // <-- GDB hangs here
20004096:   pop     {pc}

I have tried to reproduce the problem with inline assembly but for some reason the following example just worked:

void f() {
  static uint8_t stack[256]{};
  stack[255] = 4;

  asm volatile("\n\t"
               "push    {lr}"
               "\n\t"

               // pre-conditions
               "movs    r7, %[stack]"
               "\n\t"
               "movs    r6, #1"
               "\n\t"

               "movs    r0, r6"
               "\n\t"
               "ldmia   r7!, {r1, r6}"
               "\n\t"
               "push    {r0, r1}"
               "\n\t"
               "1:"
               "\n\t"
               "str.w   r6, [r7, #-4]!"
               "\n\t"
               "ldr     r6, [sp, #0]"
               "\n\t"
               "pop     {r0, r1}"
               "\n\t"
               "adds    r0, #1"
               "\n\t"
               "cmp     r0, r1"
               "\n\t"
               "itt     lt"
               "\n\t"
               "pushlt  {r0, r1}"
               "\n\t"

               // Original instruction
               //"blt.w   0x20004082"  //   ; unpredictable <IT:lt>

               // Trying to fake it
               "blt.w   1b"
               "\n\t"

               "pop     {pc}"
               "\n\t"
               :
               : [stack] "r"(&stack[255]));
}

The only real major difference I see to the other code snipped is that the inline assembly is running from flash memory where as the original code runs in ram? Maybe that's a clue somehow? 

Quickly reading through already reported ARM bugs I think this might be related:
https://bugs.launchpad.net/qemu/+bug/1364501
At least the symptoms sound identical.


The versions I'm running are:
QEMU 3.0.0
arm-none-eabi-gdb 8.2

I've also captured some trace output for single stepping from the pushlt to the blt.w instruction with the trace arguments unimp, guest_errors, op, int, exec.